Q. Two energy levels of an electron in an atom are separated by $2.3\ eV$. The frequency of radiation emitted when the electrons goes from higher to the lower level is
A) $6.95 \times 10^{14}Hz$
B) $3.68 \times 10^{15}Hz$
C) $5.6 \times 10^{14}Hz$
D) $9.11 \times 10^{15}Hz$
Explanation
(c) [image:13_image23.emf]
$E_{2} - E_{1} = hv$ or $v = \frac{E_{2} - E_{1}}{h} = \frac{2.3 \times 1.6 \times 10^{- 19}J}{6.6 \times 10^{- 34}Js}$
$= 0.56 \times 10^{15}s^{- 1} = 5.6 \times 10^{14}Hz$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.