Q. In the Bohr’s hydrogen atom model, the radius of the stationary orbit is directly proportional to ($n =$ principle quantum number)

A) $n^{- 1}$
B) $n$
C) $n^{- 2}$
D) $n^{2}$
Explanation

(d) Bohr radius $r = \frac{\varepsilon_{0}n^{2}h^{2}}{\pi Zme^{2}};\therefore r \propto n^{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Nuclei MCQs