Q. When $\ _{92}U^{235}$ is bombarded with one neutron, fission occurs and the products are three neutrons, $\ _{36}Kr^{94}$ , and
A) $\ _{56}Ba^{141}$
B) $\ _{54}Xe^{139}$
C) $\ _{56}Ba^{139}$
D) $\ _{58}I^{142}$
Explanation
(c) When a slow neutron strikes a $U^{235}\ $nucleus it is absorbed by the nucleus and the following reaction occurs.
$\ _{92}U^{235}\ + \ \ _{0}n^{1} \rightarrow \ _{36}Kr^{94}\ + \ \ _{56}Ba^{139}\ + {\ 3}_{0}n^{1} + \ energy$
Hence, $\ _{56}Ba^{139}$ is another product.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.