(d) $(rm) = \left( \frac{m^{2}}{Z} \right)(0.53\mathring{\mathrm{A}}) = (n \times 0.53\mathring{\mathrm{A}}) \Rightarrow \frac{m^{2}}{Z} = n$
$m = 5$ for $\ _{100}Fm^{257}$ [the outermost shell]
and $z = 100 \Rightarrow n = \frac{(5)^{2}}{100} = \frac{1}{4}$