Q. Radioactive $\ _{27}^{60}Co$ is transformed into stable $\ _{28}^{60}Ni$ by emitting two $\gamma$-rays of energies

A) 1.33 MeV and 1.17 MeV in succession
B) 1.17 MeV and 1.33 MeV in succession
C) 1.37 MeV and 1.13 MeV in succession
D) 1.13 MeV and 1.37 MeV in succession
Explanation

(b) The successive emission of gamma rays of energies 1.17 MeV and 1.33 MeV from the deexcitation of $\ _{28}^{60}Ni$ nuclei formed from $\beta -$decay of $\ _{27}^{60}Co$. This process is as shown in the figure through an energy level diagram
[image:13_image24.emf]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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