Q. An electron changes its position from orbit $n = 4$ to the orbit $n = 2$ of an atom. The wavelength of the emitted radiation is ($R =$ Rydberg’s constant)
A) $\frac{16}{R}$
B) $\frac{16}{3R}$
C) $\frac{16}{5R}$
D) $\frac{16}{7R}$
Explanation
(b) $\frac{1}{\lambda} = R\left\lbrack \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right\rbrack = R\left\lbrack \frac{1}{(2)^{2}} - \frac{1}{(4)^{2}} \right\rbrack \Rightarrow \lambda = \frac{16}{3R}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.