(d) $R = \frac{2\pi^{2}k^{2}e^{4}m}{ch^{3}} = \left( \frac{1}{4\pi\varepsilon_{0}} \right)^{2}\frac{2\pi^{2}me^{4}}{ch^{3}}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.