Q. In a beryllium atom, if $a_{0}$ be the radius of the first orbit, then the radius of the second orbit will be will be in general
A) $na_{0}$
B) $a_{0}$
C) $n^{2}a_{0}$
D) $\frac{a_{0}}{n^{2}}$
Explanation
(c) $r \propto n^{2} \Rightarrow r_{n} = n^{2}a_{0}\ \lbrack\because r_{1} = a_{0}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.