Q. A nucleus $\ _{n}X^{m}$emits one $\alpha\ $and one $\beta$-particle. The resulting nucleus is
A) $\ _{n}X^{m - 4}$
B) $\ _{n - 2}X^{m - 4}$
C) $\ _{n - 4}Z^{m - 4}$
D) $\ _{n - 1}Z^{m - 4}$
Explanation
(d) Decrease in mass number $= 4$
Decreases in charge number $= 2 - 1 = 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.