Q. If a proton and anti-proton come close to each other and annihilate, how much energy will be released
A) $1.5 \times 10^{- 10}J$
B) $3 \times 10^{- 10}J$
C) $4.5 \times 10^{- 10}J$
D) None of these
Explanation
(b) Mass of proton = mass of antiproton
$= 1.67 \times 10^{- 27}kg = 1amu$
Energy equivalent to $1\ amu = 931\ MeV$
So energy equivalent to $2\ amu = 2 \times 931\ MeV$
$= 1862 \times 10^{6} \times 1.6 \times 10^{- 19}$
$= 2.97 \times 10^{- 10}J = 3 \times 10^{- 10}J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.