(d) Energy radiated $= 1.4\ kW/m^{2}$
$= 1.4\ kJ/s\ m^{2} = \frac{1.4\ kJ}{\frac{1}{86400}day\ m^{2}} = \frac{1.4 \times 86400\ kJ}{day\ m^{2}}$
Total energy radiated/day
$= \frac{4\pi \times \left( 1.5 \times 10^{11} \right)^{2} \times 1.4 \times 86400}{1}\frac{kJ}{day} = E$
$\therefore E = mc^{2} \Rightarrow m = \frac{E}{c^{2}}$
$= \frac{4\pi \times \left( 1.5 \times 10^{11} \right)^{2} \times 1.4 \times 86400}{\left( 3 \times 10^{8} \right)^{2}} \times 10^{3} = 3.8 \times 10^{14}kg$