Q. The sun radiates energy in all directions. The average radiations received on the earth surface from the sun is $1.4\ kilowatt/m^{2}$. The average earth sun distance is $1.5 \times 10^{11}metres$. The mass lost by the sun per day is $(1\ day = 86400\ seconds)$

A) $4.4 \times 10^{9}kg$
B) $7.6 \times 10^{14}kg$
C) $3.8 \times 10^{12}kg$
D) $3.8 \times 10^{14}kg$
Explanation

(d) Energy radiated $= 1.4\ kW/m^{2}$
$= 1.4\ kJ/s\ m^{2} = \frac{1.4\ kJ}{\frac{1}{86400}day\ m^{2}} = \frac{1.4 \times 86400\ kJ}{day\ m^{2}}$
Total energy radiated/day
$= \frac{4\pi \times \left( 1.5 \times 10^{11} \right)^{2} \times 1.4 \times 86400}{1}\frac{kJ}{day} = E$
$\therefore E = mc^{2} \Rightarrow m = \frac{E}{c^{2}}$
$= \frac{4\pi \times \left( 1.5 \times 10^{11} \right)^{2} \times 1.4 \times 86400}{\left( 3 \times 10^{8} \right)^{2}} \times 10^{3} = 3.8 \times 10^{14}kg$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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