Explanation

(d) $\beta$-emission takes place from a radioactive nucleus as
$\ \ \ \ \ \ \ \ _{15}^{32}P\overset{- \beta\ \ \ }{\rightarrow}_{16}^{32}S +_{- 1}e^{0} + \overline{v}$$_{1}$
Where $\overline{v}$ is the anti-neutrino.
In $\beta^{+}$ decay a positron is emitted as
$\ \ \ \ \ \ \ \ _{11}^{22}{Na}\ \rightarrow \ _{10}^{22}{Ne} +_{- 1}e^{0} + v$