Q. Radioactive element decays to form a stable nuclide, then the rate of decay of reactant $\left( \frac{dN}{dt} \right)$ will vary with time $(t)$ as shown in figure
A)
B)
C)
D)
Explanation
(c) $N = N_{0}e^{- \lambda t} \Rightarrow \frac{dN}{dt} = - N_{0}\lambda e^{- \lambda t}$
$i.e.,$ Rate of decay $\left( \frac{dN}{dt} \right)$ varies exponentially with time $(t)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.