Q. If the binding energy per nucleon of deutron is 1.115 $MeV$, its mass defect in atomic mass unit is
A) 0.0048
B) 0.0024
C) 0.0012
D) 0.0006
Explanation
(b) Mass defect $= \ \frac{2\ \times \ 1.115}{931}\ = 0.0024\ $unit
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.