The number of $\alpha$-particles and $\beta - particles\ $respectively emitted in the reaction $\ _{88}A^{196} \rightarrow \ _{78}B^{164}$ are

Question

Dr. Abubacker · Accepted Answer

(b) $\ _{88}A^{196} ightarrow \ _{78}B^{164}$
Number of $\alpha - particles$ $= \ \frac{196 - 164}{4}\  = 8$
$\ \ \ \ \ \ \ \ \ \ \ _{88}A^{196}\overset{- 8\alpha\ \ \ \ \ }{ightarrow}\ _{72}X^{164} ightarrow \ _{78}B^{164}$
$	herefore$ Number of $\beta - particles$ =$78 - 72 = 6$

Q. The number of $\alpha$-particles and $\beta - particles\ $respectively emitted in the reaction $\ _{88}A^{196} \rightarrow \ _{78}B^{164}$ are

Explanation

Reviewed by Dr. Abubacker

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