Q. In hydrogen atom, when electron jumps from second to first orbit, then energy emitted is
A) $- 13.6\ eV$
B) $- 27.2\ eV$
C) $- 6.8\ eV$
D) None of these
Explanation
(d) $E_{n_{1} \rightarrow n_{2}} = - 13.6\left\lbrack \frac{1}{n_{2}^{2}} - \frac{1}{n_{1}^{2}} \right\rbrack;n_{1} = 2\ \&\ n_{2} = 1$
$\Rightarrow E_{II} \rightarrow E_{I} = - 13.6 \times \frac{3}{4} = - 10.2\ eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.