Q. The possible quantum numbers for $3d$ electrons are
A) $n = 3,l = 1,m_{l} = + 1,m_{s} = - \frac{1}{2}$
B) $n = 3,l = 2,m_{l} = + 2,m_{s} = - \frac{1}{2}$
C) $n = 3,l = 1,m_{l} = - 1,m_{s} = + \frac{1}{2}$
D) $n = 3,l = 0,m_{l} = + 1,m_{s} = - \frac{1}{2}$
Explanation
The correct answer is Option B: $n = 3,l = 2,m_{l} = + 2,m_{s} = - \frac{1}{2}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.