(c) $\left( T_{1/2} \right)_{x} = \left( t_{mean} \right)_{y}$
$\Rightarrow \frac{0.693}{\lambda_{x}} = \frac{1}{\lambda_{y}} \Rightarrow \lambda_{x} = 0.693\lambda_{y}$ or $\lambda_{x} < \lambda_{y}$
Also rate of decay $= \lambda N$
Initially number of atoms $(N)$ of both are equal but since $\lambda_{y} > \lambda_{x}$, therefore, $y$ will decay at a faster rate than $x$