(c) Nuclear radius is proportional to $A^{1/3}$ , where $A\ $is the mass number of Nucleus
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ R = R_{0}A^{1/3}$
where $R_{0} = 1.2\ fm$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{R_{1}}{R_{2}} = \frac{R_{0}(216)^{1/3}}{R_{0}(125)^{1/3}} = \frac{6}{5}$