Q. The ratio of minimum to maximum wavelength in Balmer series is

A) 5 : 9
B) 5 : 36
C) 1 : 4
D) 3 : 4
Explanation

(a) $\frac{1}{\lambda} = R\left\lbrack \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right\rbrack \Rightarrow \frac{\lambda_{\min}}{\lambda_{\max}} = \frac{\left\lbrack \frac{1}{2^{2}} - \frac{1}{3^{2}} \right\rbrack}{\left\lbrack \frac{1}{2^{2}} - \frac{1}{\infty} \right\rbrack} = \frac{5}{9}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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