Q. Two protons are kept at a separation of 40$\ \mathring{\mathrm{A}}$. $F_{n}$ is the nuclear force and $F_{e}$ is the electrostatic force between them. Then
A) $F_{n} > > F_{e}$
B) $F_{n}\ = \ F_{e}$
C) $F_{n} < < F_{e}$
D) $F_{n} \approx F_{e}$
Explanation
(c) $F_{n}$ is stronger than $F_{e}.F_{n}$operates at very short range inside the nucleus as little as $10^{- 15}$ m. As in the given case two protons are kept at a separation of $40\mathring{\mathrm{A}}.F_{n} < < F_{e}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.