Q. Consider an electron in the $n^{th}$ orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength $\lambda$ of that electron as
A) $(0.259)n\lambda$
B) $\sqrt{n}\lambda$
C) $(13.6)\lambda$
D) $n\lambda$
Explanation
(d) According to Bohr’s theory $mvr = n\frac{h}{2\pi}$
$\Rightarrow$ Circumference $2\pi r = n\left( \frac{h}{mv} \right) = n\lambda$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.