A nucleus of an element $\ _{84}X^{202}$ emits an $\alpha$-particle first, a $\beta$-particle next and then a gamma photon. The final nucleus formed has an atomic number

Question

Dr. Abubacker · Accepted Answer

(c) $\ _{84}X^{202}\overset{\ \ \alpha - decay\ \ }{\rightarrow}\ _{82}Y^{198} +_{2}He^{4}$ and
$\ _{82}Y^{198}\overset{\ \ \beta - decay\ \ }{\rightarrow}\ _{83}Z^{198} +_{- 1}\beta^{0}$

Q. A nucleus of an element $\ _{84}X^{202}$ emits an $\alpha$-particle first, a $\beta$-particle next and then a gamma photon. The final nucleus formed has an atomic number

Explanation

Reviewed by Dr. Abubacker

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