When $\ _{3}Li^{7}$ nuclei are bombarded by protons, and the resultant nuclei are $\ _{4}Be^{8}$,the emitted particles will be

Question

Dr. Abubacker · Accepted Answer

(c) The nuclear reaction can be represented as
$\ _{3}Li^{7}\  + \ \ _{1}H^{1}\  \rightarrow \ _{4}Be^{8}\  + \ \ _{z}X^{A}$
Applying conservation of atomic number (charge)
$\ \ 3 + 1 = 4 + Z\  \Rightarrow \ Z = 0$
Applying conservation of atomic mass
$\ \ \ 7 + 1 = 8 + A\  \Rightarrow A = 0$
Thus, the emitted particles are $\gamma$-photons $(\ _{0}X^{0}).$

Q. When $\ _{3}Li^{7}$ nuclei are bombarded by protons, and the resultant nuclei are $\ _{4}Be^{8}$,the emitted particles will be

Explanation

Reviewed by Dr. Abubacker

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