Q. A radioactive substance has a half-life of four months. Three-fourth of the substance will decay in

A) 3 months
B) 4 months
C) 8 months
D) 12 months
Explanation

(c) From Rutherford-Soddy’s law
$N = N_{0}\left( \frac{1}{2} \right)^{n}$
Given, $N = 1 - \frac{3}{4}\ = \frac{1}{4}N_{0}\ ,\ n = \frac{t}{T}\ = \ \frac{t}{4}$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \frac{1}{4} = \left( \frac{1}{2} \right)^{t/4}$
$\Rightarrow \ \ \ \ \ \left( \frac{1}{2} \right)^{2} = \left( \frac{1}{2} \right)^{t/4}$
$\Rightarrow \ \ \ \ \ \ \ \ \ 2\ = \frac{t}{4}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ t = 8\ months$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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