Q. Ionisation energy of an electron present in the second Bohr’s orbit of hydrogen is
A) 54.4 eV
B) 13.6 eV
C) 1.5 eV
D) 3.4 eV
Explanation
(d) In the second orbit, $n = 2$
Ionisation energy, $E = \frac{13.6}{2^{2}} = 3.4\ eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.