Q. A radioactive element forms its own isotope after 3 consecutive disintegrations. The particles emitted are
A) 3 $\beta$-particles
B) 2 $\beta$-particles - 1 $\alpha$-particle
C) 2 $\beta$-particles - 1 $\gamma$-particle
D) 2 $\alpha$-particles - 1 $\beta$-particle
Explanation
(b) To form its own isotope atomic number$(Z)$ should remain same.
So, the emission of one $\alpha - particle\ and\ two\ \ \beta - particles$ will maintain the $Z$ same.
Where $\ \alpha - particle$ = $\ _{2}He^{4};\ \ \beta - particle = \ _{- 1}\beta^{0\ }$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.