Q. $\ _{92}U^{238}$ on absorbing a neutron goes over to$\ _{92}U^{239}$. This nucleus emits an electron to go over electron goes over to Plutonium. The resulting Plutonium can be expressed as
A) $\ _{94}U^{239}$
B) $\ _{92}U^{239}$
C) $\ _{93}U^{240}$
D) $\ _{92}U^{240}$
Explanation
(a) $\ _{92}U^{239} \longrightarrow \ _{94}{Pu}^{239}{+ 2(}_{- 1}e^{0)}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.