Q. As per Bohr model, the minimum energy (in $eV$) required to remove an electron from the ground state of doubly ionized $Li$ atom ($Z = 3$) is
A) 1.51
B) 13.6
C) 40.8
D) 122.4
Explanation
(d) $E = - Z^{2} \times 13.6\ eV = - 9 \times 13.6\ eV = - 122.4\ eV$
So ionization energy $= + 122.4\ eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.