Q. The binding energy per nucleon for deuteron and helium are 1.1MeV and 7.0MeV. The energy released when two deuterons fuse to form a helium nucleus is
A) 23.6MeV
B) 2.2MeV
C) 30.2MeV
D) 3.6MeV
Explanation
(a) Ratio of $n/p\ $will decrease
$2_{1}H^{2} \rightarrow \ _{2}He^{4}\ + Q$
Energy released
$Q = 4 \times 7 - 4 \times 1.1 = 23.6\ MeV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.