Q. The mass of a $\ _{3}^{7}Li$ nucleus is $0.042u$ less than the sum of the masses of all its nucleons. The binding energy per nucleon of $\ _{3}^{7}Li$ nucleus is nearly
A) $23\ MeV$
B) $46\ MeV$
C) $5.6\ MeV$
D) $3.9\ MeV$
Explanation
(c) $\frac{BE}{nucleon} = \frac{0.042 \times 931}{7} = 5.6MeV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.