Q. In nuclear reaction $\ _{2}He^{4} + \ _{z}X^{A} \rightarrow {\ _{z + 2}Y}^{A + 3} + A,A$ denotes

A) Electron
B) Positron
C) Proton
D) Neutron
Explanation

(d) The given equation is $\ _{2}He^{4} + \ _{z}X^{A} \rightarrow {\ _{z + 2}Y}^{A + 3} + A$
Applying charge and mass conservation
$4 + A = A + 3 + x \Rightarrow x = 1 \Rightarrow 2 + z = z + 2 + n \Rightarrow n = 0$
Hence $A$ is a neutron

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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