Q. A particle moving with a velocity of $\frac{1}{100}th$ of that of light will cross a nucleus on about
A) $10^{- 8}s$
B) $10^{- 12}s$
C) $6 \times 10^{- 15}s$
D) $10^{- 20}s$
Explanation
(d) $t = \frac{nuclear\ distance}{velocity} = \frac{10^{- 14}}{3 \times 10^{6}} \approx 10^{- 20}s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.