Q. Every series of hydrogen spectrum has an upper and lower limit in wavelength. The spectral series which has an upper limit of wavelength equal to $18752\ \mathring{\mathrm{A}}$ is (Rydberg constant $R = 1.097 \times 10^{7}\ per\ metre$)

A) Balmer series
B) Lyman series
C) Paschen series
D) Pfund series
Explanation

(c) $\frac{1}{\lambda} = R\left\lbrack \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right\rbrack \Rightarrow \frac{1}{n_{1}^{2}}\ - \frac{1}{n_{2}^{2}} = \frac{1}{R\lambda}$
$= \frac{1}{1.097 \times 10^{7} \times 18752 \times 10^{- 10}} = 0.0486 = \frac{7}{144}$. But $\frac{1}{3^{2}} - \frac{1}{4^{2}} = \frac{7}{144} \Rightarrow n_{1} = 3$ and $n_{2} = 4$ [Paschen series]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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