(a) $\frac{1}{\lambda} = R\left\lbrack \frac{1}{4} - \frac{1}{9} \right\rbrack = \frac{5R}{36}$ $\therefore R = \frac{36}{5\lambda} = \frac{36}{5 \times 6563 \times 10^{- 10}} = 1.09 \times 10^{7}m^{- 1}$
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Ph.D. in Physics with 19+ years of teaching experience.