Q. The energy of a hydrogen atom in its ground state is $- 13.6\ eV$. The energy of the level corresponding to the quantum number $n = 2$ (first excited state) in the hydrogen atom is
A) $- 2.72\ eV$
B) $- 0.85\ eV$
C) $- 0.54\ eV$
D) $- 3.4\ eV$
Explanation
(d) $E_{n} = \frac{- 13.6}{n^{2}} = \frac{- 13.6}{4} = - 3.4eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.