Q. Minimum excitation potential of Bohr’s first orbit in hydrogen atom is
A) $13.6\ V$
B) $3.4\ V$
C) $10.2\ V$
D) $3.6\ V$
Explanation
(c) Excitation potential $= \frac{Excitation\ energy}{e}$
Minimum excitation energy corresponds to excitation from $n = 1$ to $n = 2$
$\therefore$ Minimum excitation energy in hydrogen atom $= - 3.4 - ( - 13.6) = + 10.2eV$
So minimum excitation potential $= 10.2V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.