(b) $\frac{N}{N_{0}} = \left( \frac{1}{2} \right)^{t/T} = \left( \frac{1}{2} \right)^{\frac{10}{5}} = \left( \frac{1}{2} \right)^{2} = \frac{1}{4}25\%$
This is probability of remaining portion of radium.
So, probability of decay
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = (10$0-25)%= 75%