The binding energy per nucleon of $O^{16}$ is $7.97MeV$ and that of $O^{17}$ is $7.75\ MeV$. The energy (in $MeV$) required to remove a neutron from $O^{17}$ is

Question

Dr. Abubacker · Accepted Answer

(c) The equation is $O^{17} ightarrow_{0}n^{1} + O^{16}$
$	herefore$ Energy required = B.E. of $O^{17} -$ B.E. of $O^{16}$
$= 17 	imes 7.75 - 16 	imes 7.97 = 4.23\ MeV$

Q. The binding energy per nucleon of $O^{16}$ is $7.97MeV$ and that of $O^{17}$ is $7.75\ MeV$. The energy (in $MeV$) required to remove a neutron from $O^{17}$ is

Explanation

Reviewed by Dr. Abubacker

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