In the uranium radioactive series, the initial nucleus is $\ _{92}U^{238}$ and that the final nucleus is $\ _{82}{Pb}^{206}$. When uranium nucleus decays to lead, the number of $\alpha$-particle and $\beta$-particles emitted are

Question

Dr. Abubacker · Accepted Answer

(a) Let number of $\alpha$-particles emitted be $x$ and number of $\beta$-particles emitted be $y$.
Difference in mass number $4x = 238 - 206 = 32$
$x = 8$
Difference in charge number $2x - 1y = 92 - 82 = 10$
$16 - y = 10,y = 6$

Q. In the uranium radioactive series, the initial nucleus is $\ _{92}U^{238}$ and that the final nucleus is $\ _{82}{Pb}^{206}$. When uranium nucleus decays to lead, the number of $\alpha$-particle and $\beta$-particles emitted are

Explanation

Reviewed by Dr. Abubacker

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