Q. The ratio of the energies of the hydrogen atom in its first to second excited state is
A) 1/4
B) 4/9
C) 9/4
D) 4
Explanation
(c) First excited state $i.e.,$ second orbit $(n = 2)$
Second excited state $i.e.,$ third orbit $(n = 3)$
$\because E = - \frac{13.6}{n^{2}} \Rightarrow \frac{E_{2}}{E_{3}} = \left( \frac{3}{2} \right)^{2} = \frac{9}{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.