Q. $\binom{235}{92}X \rightarrow \binom{231}{91}Y$ Number of particles emitted in the reaction is
A) One electron and one neutron
B) One neutron and one electron
C) One $\alpha$ and one neutron
D) One $\alpha\ $and one electron
Explanation
(d) The complete reaction is
$_{93}^{235}X\ \ \rightarrow \ _{91}^{231}Y\ \ \ \ {+ \ \ \ }_{\ \ 2}He^{4}\ \ \ \ {+ \ \ }_{- 1}e^{0}$
($\alpha - particle)\ \ (electron)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.