If the binding energy per nucleon in $_{3}^{7}{Li\ and\ _{2}^{4}{He}}$ nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction $p\ +_{3}^{7}{Li\ \rightarrow 2\ _{2}^{4}{He}}$ energy of proton must be

Question

Dr. Abubacker · Accepted Answer

(b) Energy of proton $+ 7 	imes \ 5.60\  = 2\  	imes \lbrack 4 	imes \ 7.06brack$
$	herefore$ Energy of proton $= \ 17.28\ MeV$

Q. If the binding energy per nucleon in $_{3}^{7}{Li\ and\ _{2}^{4}{He}}$ nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction $p\ +_{3}^{7}{Li\ \rightarrow 2\ _{2}^{4}{He}}$ energy of proton must be

Explanation

Reviewed by Dr. Abubacker

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