Q. If the mass number of an atom is $A = 0$ and its electron configuration is $1s^{2},2s^{2},2p^{6},3s^{2},3p^{6}$, the number of neutrons and protons in its nucleus will be

A) 22, 18
B) 18, 22
C) 20, 20
D) 18, 18
Explanation

(a) Number of protons $= 2 + 2 + 6 + 2 + 6 = 18$
Number of neutrons $= 40 - 18 = 22$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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