Q. The wavelength of light emitted from second orbit to first orbits in a hydrogen atom is
A) $1.215 \times 10^{- 7}m$
B) $1.215 \times 10^{- 5}m$
C) $1.215 \times 10^{- 4}m$
D) $1.215 \times 10^{- 3}m$
Explanation
(a) Energy constant $E = 10.2eV = 10.2 \times 1.6 \times 10^{- 19}J$
$\Rightarrow E = \frac{hc}{\lambda} \Rightarrow \lambda = 1.215 \times 10^{- 7}m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.