Q. An element $A$ decays into element $C$ by a two step process $A \rightarrow B +_{2}He^{4}$ $B \rightarrow C + 2_{- 1}e^{0}$ Then
A) $A$ and $C$ are isotopes
B) $A$ and $C$ are isobars
C) $A$ and $B$ are isotopes
D) $A$ and $B$ are isobars
Explanation
(a) $A$ and $C$ are isotopes as their charge number is same
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.