$_{2}^{4}{He} +_{4}^{9}{Be} \rightarrow \ _{0}^{1}n + \ ?$ The missing ion in the above nuclear reaction is

Question

Dr. Abubacker · Accepted Answer

(c) From the conservation of mass number and charge number
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{2}^{4}{He} +_{4}^{9}{Be} \rightarrow_{0}^{1}n +_{6}^{12}X$
Here, $X$ can be carbon.

Q. $_{2}^{4}{He} +_{4}^{9}{Be} \rightarrow \ _{0}^{1}n + \ ?$ The missing ion in the above nuclear reaction is

Explanation

Reviewed by Dr. Abubacker

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