Neutron decay in free space is given as follows $\ _{0}n^{1} \rightarrow {\ _{1}H}^{1} + -_{1}e^{0} + \lbrack\ \rbrack$ Then the parenthesis represents a

Question

Dr. Abubacker · Accepted Answer

(c) An electron is accompanied by an antineutrino.

Q. Neutron decay in free space is given as follows $\ _{0}n^{1} \rightarrow {\ _{1}H}^{1} + -_{1}e^{0} + \lbrack\ \rbrack$ Then the parenthesis represents a

Explanation

Reviewed by Dr. Abubacker

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