Q. For principal quantum number $n = 3$, the possible values of orbital quantum number $'l'$ are

A) 1, 2, 3
B) 0, 1, 2, 3
C) 0, 1, 2
D) $- 1,\ 0,\ + 1$
Explanation

(c) $\therefore$ Orbital quantum number has values : 0 to $(n - 1)$
For $n = 3$, orbital quantum number $l = 0,\ 1,\ 2$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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