An energy of $24.6\ eV$ is required to remove one of the electrons from a neutral helium atom. The energy (in $eV$) required to remove both the electrons from a neutral helium atom is

Question

Dr. Abubacker · Accepted Answer

(a) After the removal of first electron remaining atom will be hydrogen like atom
So energy required to remove second electron from the atom $E = 13.6 	imes \frac{2^{2}}{1} = 54.4eV$
$	herefore$ Total energy required $= 24.6 + 54.4 = 79\ eV$

Q. An energy of $24.6\ eV$ is required to remove one of the electrons from a neutral helium atom. The energy (in $eV$) required to remove both the electrons from a neutral helium atom is

Explanation

Reviewed by Dr. Abubacker

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